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										 |  |  | subroutine lorentzian(y,npts,a)
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							|  |  |  | ! Input:  y(npts); assume x(i)=i, i=1,npts
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										 |  |  | ! Output: a(1:5)
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										 |  |  | !         a(1) = baseline
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							|  |  |  | !         a(2) = amplitude
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							|  |  |  | !         a(3) = x0
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							|  |  |  | !         a(4) = width
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										 |  |  | !         a(5) = chisqr
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							|  |  |  |   real y(npts)
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										 |  |  |   real a(5)
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										 |  |  |   real deltaa(4)
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							|  |  |  | 
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							|  |  |  |   a=0.
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							|  |  |  |   df=12000.0/8192.0                               !df = 1.465 Hz
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							|  |  |  |   width=0.
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										 |  |  |   ipk=0
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										 |  |  |   ymax=-1.e30
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							|  |  |  |   do i=1,npts
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							|  |  |  |      if(y(i).gt.ymax) then
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							|  |  |  |         ymax=y(i)
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							|  |  |  |         ipk=i
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							|  |  |  |      endif
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							|  |  |  | !     write(50,3001) i,i*df,y(i)
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							|  |  |  | !3001 format(i6,2f12.3)
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							|  |  |  |   enddo
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							|  |  |  | !  base=(sum(y(ipk-149:ipk-50)) + sum(y(ipk+51:ipk+150)))/200.0
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							|  |  |  |   base=(sum(y(1:20)) + sum(y(npts-19:npts)))/40.0
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							|  |  |  |   stest=ymax - 0.5*(ymax-base)
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							|  |  |  |   ssum=y(ipk)
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							|  |  |  |   do i=1,50
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							|  |  |  |      if(ipk+i.gt.npts) exit
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							|  |  |  |      if(y(ipk+i).lt.stest) exit
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							|  |  |  |      ssum=ssum + y(ipk+i)
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							|  |  |  |   enddo
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							|  |  |  |   do i=1,50
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							|  |  |  |      if(ipk-i.lt.1) exit
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							|  |  |  |      if(y(ipk-i).lt.stest) exit
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							|  |  |  |      ssum=ssum + y(ipk-i)
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							|  |  |  |   enddo
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							|  |  |  |   ww=ssum/y(ipk)
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							|  |  |  |   width=2
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							|  |  |  |   t=ww*ww - 5.67
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							|  |  |  |   if(t.gt.0.0) width=sqrt(t)
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							|  |  |  |   a(1)=base
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							|  |  |  |   a(2)=ymax-base
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							|  |  |  |   a(3)=ipk
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							|  |  |  |   a(4)=width
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							|  |  |  | 
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							|  |  |  | ! Now find Lorentzian parameters
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							|  |  |  |   deltaa(1)=0.1
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							|  |  |  |   deltaa(2)=0.1
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							|  |  |  |   deltaa(3)=1.0
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							|  |  |  |   deltaa(4)=1.0
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							|  |  |  |   nterms=4
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							|  |  |  | !  Start the iteration
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							|  |  |  |   chisqr=0.
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							|  |  |  |   chisqr0=1.e6
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							|  |  |  |   do iter=1,5
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							|  |  |  |      do j=1,nterms
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							|  |  |  |         chisq1=fchisq0(y,npts,a)
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							|  |  |  |         fn=0.
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							|  |  |  |         delta=deltaa(j)
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							|  |  |  | 10      a(j)=a(j)+delta
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							|  |  |  |         chisq2=fchisq0(y,npts,a)
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							|  |  |  |         if(chisq2.eq.chisq1) go to 10
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							|  |  |  |         if(chisq2.gt.chisq1) then
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							|  |  |  |            delta=-delta                      !Reverse direction
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							|  |  |  |            a(j)=a(j)+delta
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							|  |  |  |            tmp=chisq1
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							|  |  |  |            chisq1=chisq2
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							|  |  |  |            chisq2=tmp
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							|  |  |  |         endif
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							|  |  |  | 20      fn=fn+1.0
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							|  |  |  |         a(j)=a(j)+delta
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							|  |  |  |         chisq3=fchisq0(y,npts,a)
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							|  |  |  |         if(chisq3.lt.chisq2) then
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							|  |  |  |            chisq1=chisq2
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							|  |  |  |            chisq2=chisq3
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							|  |  |  |            go to 20
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							|  |  |  |         endif
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							|  |  |  | ! Find minimum of parabola defined by last three points
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							|  |  |  |         delta=delta*(1./(1.+(chisq1-chisq2)/(chisq3-chisq2))+0.5)
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							|  |  |  |         a(j)=a(j)-delta
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							|  |  |  |         deltaa(j)=deltaa(j)*fn/3.
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							|  |  |  | !          write(*,4000) iter,j,a,chisq2
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							|  |  |  | !4000      format(i1,i2,4f10.4,f11.3)
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							|  |  |  |      enddo
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							|  |  |  |      chisqr=fchisq0(y,npts,a)
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							|  |  |  | !       write(*,4000) 0,0,a,chisqr
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										 |  |  |      if(chisqr/chisqr0.gt.0.99) exit
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										 |  |  |      chisqr0=chisqr
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							|  |  |  |   enddo
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										 |  |  |   a(5)=chisqr
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							|  |  |  |   return
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							|  |  |  | end subroutine lorentzian
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