2013-08-10 15:29:55 +00:00
										 
									 
								 
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								subroutine afc9(c3,npts,fsample,a,syncpk)
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								  complex c3(0:npts-1)
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								  real a(3),deltaa(3)
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								  a(1)=0.                                   !f0
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								  a(2)=0.                                   !f1
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								  a(3)=0.                                   !f2
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								  deltaa(1)=0.2
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								  deltaa(2)=0.01
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								  deltaa(3)=0.01
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								  nterms=3
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								! Start the iteration
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								  chisqr=0.
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								  chisqr0=1.e6
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								  do iter=1,4                               !One iteration is enough?
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								     do j=1,nterms
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								        chisq1=fchisq(c3,npts,fsample,a)
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								        fn=0.
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								        delta=deltaa(j)
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								10      a(j)=a(j)+delta
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								        chisq2=fchisq(c3,npts,fsample,a)
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								        if(chisq2.eq.chisq1) go to 10
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								        if(chisq2.gt.chisq1) then
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								           delta=-delta                      !Reverse direction
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								           a(j)=a(j)+delta
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								           tmp=chisq1
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								           chisq1=chisq2
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								           chisq2=tmp
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								        endif
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								20      fn=fn+1.0
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								        a(j)=a(j)+delta
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								        chisq3=fchisq(c3,npts,fsample,a)
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								        if(chisq3.lt.chisq2) then
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								           chisq1=chisq2
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								           chisq2=chisq3
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								           go to 20
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								        endif
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								! Find minimum of parabola defined by last three points
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								        delta=delta*(1./(1.+(chisq1-chisq2)/(chisq3-chisq2))+0.5)
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								        a(j)=a(j)-delta
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								        deltaa(j)=deltaa(j)*fn/3.
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								!        write(*,4000) iter,j,a,deltaa,-chisq2
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								!4000    format(i1,i2,6f10.4,f9.3)
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								     enddo
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								     chisqr=fchisq(c3,npts,fsample,a)
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								     if(chisqr/chisqr0.gt.0.9999) exit
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								     chisqr0=chisqr
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								  enddo
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								  syncpk=-chisqr
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								!  write(*,4001) a,deltaa,-chisq2
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								!4001 format(3x,6f10.4,f9.3)
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								  return
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								end subroutine afc9
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