2012-11-28 01:57:45 +00:00
										 
									 
								 
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								subroutine packmsg(msg,dat,text)
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								  parameter (NBASE=37*36*10*27*27*27)
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								  parameter (NBASE2=262178562)
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								  character*22 msg
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								  integer dat(12)
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								  character*12 c1,c2
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								  character*4 c3
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								  character*6 grid6
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								  logical text1,text2,text3,text
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								  text=.false.
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								! Convert all letters to upper case
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								  iz=22
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								  do i=1,22
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								     if(msg(i:i).ge.'a' .and. msg(i:i).le.'z')                       &
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								          msg(i:i)= char(ichar(msg(i:i))+ichar('A')-ichar('a'))
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								     if(msg(i:i).ne.' ') iz=i
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								  enddo
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								  do iter=1,5                           !Collapse multiple blanks into one
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								     ib2=index(msg(1:iz),'  ')
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								     if(ib2.lt.1) go to 5
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								     msg=msg(1:ib2)//msg(ib2+2:)
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								     iz=iz-1
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								  enddo
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											2012-12-11 18:50:07 +00:00
										 
									 
								 
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								5 if(msg(1:6).eq.'CQ DX ') msg(3:3)='9'
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											2012-11-28 01:57:45 +00:00
										 
									 
								 
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								! See if it's a CQ message
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											2012-12-11 18:50:07 +00:00
										 
									 
								 
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								  if(msg(1:3).eq.'CQ ') then
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											2012-11-28 01:57:45 +00:00
										 
									 
								 
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								     i=3
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								! ... and if so, does it have a reply frequency?
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								     if(msg(4:4).ge.'0' .and. msg(4:4).le.'9' .and.                  &
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								          msg(5:5).ge.'0' .and. msg(5:5).le.'9' .and.                &
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								          msg(6:6).ge.'0' .and. msg(6:6).le.'9') i=7
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								     go to 1
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								  endif
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								  do i=1,22
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								     if(msg(i:i).eq.' ') go to 1       !Get 1st blank
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								  enddo
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								  go to 10                             !Consider msg as plain text
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								1 ia=i
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								  c1=msg(1:ia-1)
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								  do i=ia+1,22
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								     if(msg(i:i).eq.' ') go to 2       !Get 2nd blank
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								  enddo
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								  go to 10                             !Consider msg as plain text
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								2 ib=i
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								  c2=msg(ia+1:ib-1)
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								  do i=ib+1,22
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								     if(msg(i:i).eq.' ') go to 3       !Get 3rd blank
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								  enddo
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								  go to 10                             !Consider msg as plain text
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								3 ic=i
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								  c3='    '
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								  if(ic.ge.ib+1) c3=msg(ib+1:ic)
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								  if(c3.eq.'OOO ') c3='    '           !Strip out the OOO flag
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											2014-01-18 13:59:19 +00:00
										 
									 
								 
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								  call getpfx1(c1,k1,kk)
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								  if(kk.ne.0) go to 10                 !Tnx to DL9RDZ for reminding me!
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											2012-11-28 01:57:45 +00:00
										 
									 
								 
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								  call packcall(c1,nc1,text1)
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								  call getpfx1(c2,k2,nv2)
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								  call packcall(c2,nc2,text2)
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								  if(nv2.eq.0) then
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								     if(k1.lt.0 .or. k2.lt.0 .or. k1*k2.ne.0) go to 10
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								     if(k2.gt.0) k2=k2+450
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								     k=max(k1,k2)
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								     if(k.gt.0) then
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								        call k2grid(k,grid6)
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								        c3=grid6(:4)
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								     endif
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								  endif
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								  call packgrid(c3,ng,text3)
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								  if(nv2.eq.0 .and. (.not.text1) .and. (.not.text2) .and.           &
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								       (.not.text3)) go to 20
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								  if(nv2.gt.0) then
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								     if(nv2.eq.1) then
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								        if(c1(1:3).eq.'CQ ')  nc1=262178563 + k2
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								        if(c1(1:4).eq.'QRZ ') nc1=264002072 + k2 
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								        if(c1(1:3).eq.'DE ')  nc1=265825581 + k2
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								     endif
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								     if(nv2.eq.2) then
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								        if(c1(1:3).eq.'CQ ')  nc1=267649090 + k2
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								        if(c1(1:4).eq.'QRZ ') nc1=267698375 + k2
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								        if(c1(1:3).eq.'DE ')  nc1=267747660 + k2
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								     endif
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								     go to 20
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								  endif
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								! The message will be treated as plain text.
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								10 text=.true.
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								  call packtext(msg,nc1,nc2,ng)
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								  ng=ng+32768
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								! Encode data into 6-bit words
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								20 dat(1)=iand(ishft(nc1,-22),63)               !6 bits
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								  dat(2)=iand(ishft(nc1,-16),63)                !6 bits
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								  dat(3)=iand(ishft(nc1,-10),63)                !6 bits
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								  dat(4)=iand(ishft(nc1, -4),63)                !6 bits
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								  dat(5)=4*iand(nc1,15)+iand(ishft(nc2,-26),3)  !4+2 bits
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								  dat(6)=iand(ishft(nc2,-20),63)                !6 bits
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								  dat(7)=iand(ishft(nc2,-14),63)                !6 bits
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								  dat(8)=iand(ishft(nc2, -8),63)                !6 bits
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								  dat(9)=iand(ishft(nc2, -2),63)                !6 bits
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								  dat(10)=16*iand(nc2,3)+iand(ishft(ng,-12),15) !2+4 bits
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								  dat(11)=iand(ishft(ng,-6),63)
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								  dat(12)=iand(ng,63)
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								  return
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								end subroutine packmsg
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