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	(i) SNR no longer saturates at +20 dB (ii) a large signal in the passband no longer causes the SNR of weaker signals to be biased low.
		
			
				
	
	
		
			50 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Fortran
		
	
	
	
	
	
			
		
		
	
	
			50 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Fortran
		
	
	
	
	
	
| subroutine baseline(s,nfa,nfb,sbase)
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| 
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| ! Fit baseline to spectrum (for FT8)
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| ! Input:  s(npts)         Linear scale in power
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| ! Output: sbase(npts)    Baseline
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| 
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|   implicit real*8 (a-h,o-z)
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|   real*4 s(1920)
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|   real*4 sbase(1920)
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|   real*4 base
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|   real*8 x(1000),y(1000),a(5)
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|   data nseg/10/,npct/10/
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| 
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|   df=12000.0/3840.0                    !3.125 Hz
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|   ia=max(1,nint(nfa/df))
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|   ib=nint(nfb/df)
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|   do i=ia,ib
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|      s(i)=10.0*log10(s(i))            !Convert to dB scale
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|   enddo
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| 
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|   nterms=5
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|   nlen=(ib-ia+1)/nseg                 !Length of test segment
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|   i0=(ib-ia+1)/2                      !Midpoint
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|   k=0
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|   do n=1,nseg                         !Loop over all segments
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|      ja=ia + (n-1)*nlen
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|      jb=ja+nlen-1
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|      call pctile(s(ja),nlen,npct,base) !Find lowest npct of points
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|      do i=ja,jb
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|         if(s(i).le.base) then
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|            if (k.lt.1000) k=k+1       !Save all "lower envelope" points
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|            x(k)=i-i0
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|            y(k)=s(i)
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|         endif
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|      enddo
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|   enddo
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|   kz=k
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|   a=0.
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|   call polyfit(x,y,y,kz,nterms,0,a,chisqr)  !Fit a low-order polynomial
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|   sbase=0.0
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|   do i=ia,ib
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|      t=i-i0
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|      sbase(i)=a(1)+t*(a(2)+t*(a(3)+t*(a(4)+t*(a(5))))) + 0.65
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| !     write(51,3051) i*df,s(i),sbase(i)
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| !3051 format(3f12.3)
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|   enddo
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| 
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|   return
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| end subroutine baseline
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